t^2=3.125

Solution for t^2=3.125 equation:

t^2=3.125

We move all terms to the left:

t^2-(3.125)=0

We add all the numbers together, and all the variables

t^2-3.125=0

a = 1; b = 0; c = -3.125;
Δ = b2-4ac
Δ = 02-4·1·(-3.125)
Δ = 12.5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{12.5}}{2*1}=\frac{0-\sqrt{12.5}}{2}
=-\frac{\sqrt{}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{12.5}}{2*1}=\frac{0+\sqrt{12.5}}{2}
=\frac{\sqrt{}}{2}
$